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Grade 12th · Chemistry · Chemical Kinetics

Rate Law and Rate Constant: Formula, Order & Half-Life Derivation — Class 12 Chemistry

Master Rate Law and Rate Constant (k) for Class 12 Chemistry (NCERT Chapter 4: Chemical Kinetics). Complete formulas for reaction rate, order of reaction, integrated rate equations for zero and first order, and half-life derivations.

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Essential Formulas & Mathematical Definitions

Differential Rate Expression: Rate = -d[R]/dt = k · [A]^x · [B]^y
Overall Order of Reaction: n = x + y
Units of Rate Constant: k = (mol/L)¹⁻ⁿ · s⁻¹ (where n = overall order)
Zero Order Integrated Rate: [R] = [R]₀ - k·t | Half-Life: t₁/₂ = [R]₀ / (2k)
First Order Integrated Rate: k = (2.303 / t) · log([R]₀ / [R])
First Order Half-Life: t₁/₂ = 0.693 / k (Independent of initial concentration)
Arrhenius Equation: k = A · e^(-Ea / RT) | log(k₂/k₁) = (Ea / 2.303R) · (1/T₁ - 1/T₂)

Rate Law vs Law of Mass Action

For a general reaction aA + bB → Products, the Rate Law is an experimentally determined equation expressing reaction rate in terms of molar concentrations of reactants: Rate = k[A]^x[B]^y. Crucially, powers x and y are the orders with respect to A and B. They are determined experimentally and MAY NOT EQUAL the stoichiometric coefficients a and b. Overall order n = x + y can be zero, integer, or fractional.

Zero Order Reaction: Derivation & Characteristics

A reaction is zero order when rate is independent of reactant concentration: -d[R]/dt = k[R]⁰ = k. Integrating from t = 0 ([R] = [R]₀) to time t: [R] = [R]₀ - kt. Slope of [R] vs t graph is -k. Setting [R] = [R]₀/2 gives half-life: t₁/₂ = [R]₀ / (2k). Characteristic: Half-life of a zero-order reaction is directly proportional to initial concentration [R]₀.

First Order Reaction: Integrated Rate Equation Derivation

For a first-order reaction: -d[R]/dt = k[R]. Separating variables: d[R]/[R] = -k dt. Integrating both sides: ln[R] = -kt + C. At t = 0, [R] = [R]₀ ⇒ C = ln[R]₀. Therefore: ln([R]/[R]₀) = -kt, or k = (1/t)·ln([R]₀/[R]) = (2.303/t)·log([R]₀/[R]). When [R] = [R]₀/2: t₁/₂ = (2.303/k)·log(2) = (2.303 × 0.3010)/k = 0.693 / k. Hallmark: Half-life of a first-order reaction is completely INDEPENDENT of initial concentration.

Temperature Dependence & Arrhenius Equation

Reaction rate approximately doubles for every 10°C rise in temperature (Temperature Coefficient ≈ 2 to 3). Arrhenius explained this via activation energy (Ea): k = A·e^(-Ea/RT), where A is the frequency factor and e^(-Ea/RT) represents the fraction of molecules with kinetic energy ≥ Ea. In logarithmic form: log(k) = log(A) - Ea / (2.303·R·T). A plot of log(k) vs 1/T gives a straight line with slope = -Ea / (2.303·R).

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Exam Day Revision & Problem Solving Checklist

  • ✓Determine units of k: Zero order = mol L⁻¹ s⁻¹, First order = s⁻¹, Second order = L mol⁻¹ s⁻¹
  • ✓Remember that molecularity is theoretical and cannot be zero or fractional; order is experimental and can be 0, fraction, or negative
  • ✓Use t₁/₂ = 0.693 / k for radioactive decay calculations (all natural radioactive decays follow 1st order kinetics)
  • ✓In Arrhenius equation, ensure gas constant R = 8.314 J K⁻¹ mol⁻¹ is matched with Ea in Joules (not kJ)
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High-Yield Exam Strategy & Scoring Tips

Step-by-Step Mark Allocation

Always state the governing principle or formula first, write given values with standard SI units, substitute clearly, and highlight the final numerical answer with units in a box for full step marking.

Common Calculation Traps

Watch for unit prefixes (cm to m, minutes to seconds, g to kg, degrees to radians). In coordinate and ray optics problems, double-check Cartesian sign conventions before computing.

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Frequently Asked Exam Questions & Concept Clarifications

What is the rate law in Class 12 Chemistry?

Rate law is the mathematically determined expression in which reaction rate is given in terms of molar concentration of reactants with each term raised to some power, which may or may not be equal to the stoichiometric coefficient in the balanced chemical equation: Rate = k[A]^x[B]^y.

How do you calculate the order of a reaction from the unit of rate constant?

Use the general formula for unit of k: (mol/L)¹⁻ⁿ · s⁻¹, where n is the reaction order. If unit is s⁻¹, 1 - n = 0 ⇒ n = 1 (First order). If unit is mol L⁻¹ s⁻¹, 1 - n = 1 ⇒ n = 0 (Zero order). If unit is L mol⁻¹ s⁻¹, 1 - n = -1 ⇒ n = 2 (Second order).

Why is the half-life of a first order reaction independent of initial concentration?

In the integrated rate expression k = (2.303/t)·log([R]₀/[R]), substituting [R] = [R]₀/2 cancels [R]₀ completely, yielding t₁/₂ = 0.693 / k, which contains no concentration term.